What are the solutions to the equation solvefor a,(a+2)^2+5=(b+2)^2+5 ?

The solutions to the equation solvefor a,(a+2)^2+5=(b+2)^2+5 are a=b,a=-b-4

Find the zeros of solvefor a,(a+2)^2+5=(b+2)^2+5

The zeros of solvefor a,(a+2)^2+5=(b+2)^2+5 are a=b,a=-b-4

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solve for

a, (a + 2)^{2} + 5 = (b + 2)^{2} + 5

a = b, a = - b - 4

Solution steps

(a + 2)^{2} + 5 = (b + 2)^{2} + 5

Move

5

to the right side

(a + 2)^{2} = (b + 2)^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a + 2 = (b + 2)^{2} : a = b

Solve

a + 2 = - (b + 2)^{2} : a = - b - 4

The solutions to the quadratic equation are:

a = b, a = - b - 4

x, s (x) = x (x - 3)

x^{2} - 125 = - 25

x, p = 36 x^{2} - 9 y^{2}

x, x^{2} + y^{2} + 2 x y - 2 x - 2 y - 15 = 0

(b - c) \cdot x^{2} + (c - a) x + (a - b) = 0

What are the solutions to the equation solvefor a,(a+2)^2+5=(b+2)^2+5 ?
The solutions to the equation solvefor a,(a+2)^2+5=(b+2)^2+5 are a=b,a=-b-4
Find the zeros of solvefor a,(a+2)^2+5=(b+2)^2+5
The zeros of solvefor a,(a+2)^2+5=(b+2)^2+5 are a=b,a=-b-4