What are the solutions to the equation (a+c)(a-c)=0 ?

The solutions to the equation (a+c)(a-c)=0 are c=-a,c=a

Find the zeros of (a+c)(a-c)=0

The zeros of (a+c)(a-c)=0 are c=-a,c=a

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(a + c) (a - c) = 0

c = - a, c = a

Solution steps

(a + c) (a - c) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a + c = 0 or a - c = 0

Solve

a + c = 0 : c = - a

Solve

a - c = 0 : c = a

The solutions to the quadratic equation are:

c = - a, c = a

x, ((p - 3) (p + 5)) \cdot x^{2} - 4 x + 8 = 0

x lo g_{10} (10) (x - 3) = 2

x, 2 x^{2} - 4 x y + 2 y^{2} - 5 x - 5 = 0

x, z^{2} = \frac{324}{972} (x^{2} + y^{2})

x, x^{2} - 3 x - m (m + 3) = 0

What are the solutions to the equation (a+c)(a-c)=0 ?
The solutions to the equation (a+c)(a-c)=0 are c=-a,c=a
Find the zeros of (a+c)(a-c)=0
The zeros of (a+c)(a-c)=0 are c=-a,c=a