What are the solutions to the equation solvefor x,x^2-3x-m(m+3)=0 ?

The solutions to the equation solvefor x,x^2-3x-m(m+3)=0 are x=-m,x=m+3

Find the zeros of solvefor x,x^2-3x-m(m+3)=0

The zeros of solvefor x,x^2-3x-m(m+3)=0 are x=-m,x=m+3

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x, x^{2} - 3 x - m (m + 3) = 0

x = - m, x = m + 3

Solution steps

x^{2} - 3 x - m (m + 3) = 0

Expand

x^{2} - 3 x - m (m + 3) : x^{2} - 3 x - m^{2} - 3 m

x^{2} - 3 x - m^{2} - 3 m = 0

Factor

x^{2} - 3 x - m^{2} - 3 m : (x + m) (x - m - 3)

(x + m) (x - m - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + m = 0 or x - m - 3 = 0

Solve

x + m = 0 : x = - m

Solve

x - m - 3 = 0 : x = m + 3

The solutions to the quadratic equation are:

x = - m, x = m + 3

x, 3 x^{2} y + 2 y = 5 x

\frac{5 ( x ^{2} + 1 )}{25} = 10

n (t) = 0.1 t^{2} - 4 t + 90

a, f + f^{2} = - a^{2}

z, r^{2} \cdot p^{2} \cdot z^{2} + 2 r p z + 1 = 0

What are the solutions to the equation solvefor x,x^2-3x-m(m+3)=0 ?
The solutions to the equation solvefor x,x^2-3x-m(m+3)=0 are x=-m,x=m+3
Find the zeros of solvefor x,x^2-3x-m(m+3)=0
The zeros of solvefor x,x^2-3x-m(m+3)=0 are x=-m,x=m+3