What are the solutions to the equation 2/7*x^2+3/4*x= 1/4*x ?

The solutions to the equation 2/7*x^2+3/4*x= 1/4*x are x=0,x=-7/4

Find the zeros of 2/7*x^2+3/4*x= 1/4*x

The zeros of 2/7*x^2+3/4*x= 1/4*x are x=0,x=-7/4

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\frac{2}{7} \cdot x^{2} + \frac{3}{4} \cdot x = \frac{1}{4} \cdot x

x = 0, x = - \frac{7}{4}

Decimal Notation

x = 0, x = - 1.75

Solution steps

\frac{2}{7} x^{2} + \frac{3}{4} x = \frac{1}{4} x

Find Least Common Multiplier of

7, 4 : 28

Multiply by LCM=

28

\frac{2}{7} x^{2} \cdot 28 + \frac{3}{4} x \cdot 28 = \frac{1}{4} x \cdot 28

Simplify

8 x^{2} + 21 x = 7 x

Move

7 x

to the left side

8 x^{2} + 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

1 4^{2} - 4 \cdot 8 \cdot 0 = 14

x_{1, 2} = \frac{- 14 \pm 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 14 + 14}{2 \cdot 8}, x_{2} = \frac{- 14 - 14}{2 \cdot 8}

x = \frac{- 14 + 14}{2 \cdot 8} : 0

x = \frac{- 14 - 14}{2 \cdot 8} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{4}

x, \frac{x ^{2}}{9} - \frac{y ^{2}}{16} = \frac{z}{4}

\frac{x + 3}{4 - 3} = \frac{( x + 5 ) ( x - 2 )}{3}

\frac{x ^{2} - ( 17 x )}{4 + 1} = 0

2 p^{2} + k^{3} = 15

(x) = - 5 (x + 20) \cdot (x - 80)

What are the solutions to the equation 2/7*x^2+3/4*x= 1/4*x ?
The solutions to the equation 2/7*x^2+3/4*x= 1/4*x are x=0,x=-7/4
Find the zeros of 2/7*x^2+3/4*x= 1/4*x
The zeros of 2/7*x^2+3/4*x= 1/4*x are x=0,x=-7/4