What are the solutions to the equation 6k=k^2 ?

The solutions to the equation 6k=k^2 are k=6,k=0

Find the zeros of 6k=k^2

The zeros of 6k=k^2 are k=6,k=0

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6 k = k^{2}

k = 6, k = 0

Solution steps

6 k = k^{2}

Switch sides

k^{2} = 6 k

Move

6 k

to the left side

k^{2} - 6 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

k_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, k_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

k = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

k = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 6, k = 0

x^{2} = a^{2} + b^{2}

e = 0.5 + 2.7 \cdot 1 0^{- 2} t + 2.8 \cdot 1 0^{- 5} t^{2}

(\frac{5}{3})^{2} x \cdot (\frac{3}{5})^{9} x = 1

2 2 1^{2} + 4^{2} = c^{2}

x, x^{2} - 2 x + y^{2} - 4 y + 5 = 0

What are the solutions to the equation 6k=k^2 ?
The solutions to the equation 6k=k^2 are k=6,k=0
Find the zeros of 6k=k^2
The zeros of 6k=k^2 are k=6,k=0