What are the solutions to the equation x(x-5)-x+5=0 ?

The solutions to the equation x(x-5)-x+5=0 are x=5,x=1

Find the zeros of x(x-5)-x+5=0

The zeros of x(x-5)-x+5=0 are x=5,x=1

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x (x - 5) - x + 5 = 0

x = 5, x = 1

Solution steps

x (x - 5) - x + 5 = 0

Expand

x (x - 5) - x + 5 : x^{2} - 6 x + 5

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

x, v (4 - v (4 + v (4 - x))) = x^{2} - 4

d^{3} - d^{2} - 6 d = 1 + x^{2}

3 x^{2} - 13 x - 10 = \frac{5 - 2}{3}

x, (x - 1)^{2} + (y + 3)^{2} + 3 = 0

y, x^{2} + y^{2} + x y = x

What are the solutions to the equation x(x-5)-x+5=0 ?
The solutions to the equation x(x-5)-x+5=0 are x=5,x=1
Find the zeros of x(x-5)-x+5=0
The zeros of x(x-5)-x+5=0 are x=5,x=1