What are the solutions to the equation d^3-d^2-6d=1+x^2 ?

The solutions to the equation d^3-d^2-6d=1+x^2 are x=sqrt(d^3-d^2-6d-1),x=-sqrt(d^3-d^2-6d-1)

Find the zeros of d^3-d^2-6d=1+x^2

The zeros of d^3-d^2-6d=1+x^2 are x=sqrt(d^3-d^2-6d-1),x=-sqrt(d^3-d^2-6d-1)

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d^{3} - d^{2} - 6 d = 1 + x^{2}

x = d^{3} - d^{2} - 6 d - 1, x = - d^{3} - d^{2} - 6 d - 1

Solution steps

d^{3} - d^{2} - 6 d = 1 + x^{2}

Switch sides

1 + x^{2} = d^{3} - d^{2} - 6 d

Move

1

to the right side

x^{2} = d^{3} - d^{2} - 6 d - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = d^{3} - d^{2} - 6 d - 1, x = - d^{3} - d^{2} - 6 d - 1

3 x^{2} - 13 x - 10 = \frac{5 - 2}{3}

x, (x - 1)^{2} + (y + 3)^{2} + 3 = 0

y, x^{2} + y^{2} + x y = x

x, x^{2} + y^{2} - x y = 4

x^{2} + 5 x - a = 0

What are the solutions to the equation d^3-d^2-6d=1+x^2 ?
The solutions to the equation d^3-d^2-6d=1+x^2 are x=sqrt(d^3-d^2-6d-1),x=-sqrt(d^3-d^2-6d-1)
Find the zeros of d^3-d^2-6d=1+x^2
The zeros of d^3-d^2-6d=1+x^2 are x=sqrt(d^3-d^2-6d-1),x=-sqrt(d^3-d^2-6d-1)