What are the solutions to the equation x^2+5x-a=0 ?

The solutions to the equation x^2+5x-a=0 are x=(-5+sqrt(25+4a))/2 ,x=(-5-sqrt(25+4a))/2

Find the zeros of x^2+5x-a=0

The zeros of x^2+5x-a=0 are x=(-5+sqrt(25+4a))/2 ,x=(-5-sqrt(25+4a))/2

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x^{2} + 5 x - a = 0

x = \frac{- 5 + 25 + 4 a}{2}, x = \frac{- 5 - 25 + 4 a}{2}

Solution steps

x^{2} + 5 x - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - a )}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot (- a) : 25 + 4 a

x_{1, 2} = \frac{- 5 \pm 25 + 4 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 25 + 4 a}{2 \cdot 1}, x_{2} = \frac{- 5 - 25 + 4 a}{2 \cdot 1}

x = \frac{- 5 + 25 + 4 a}{2 \cdot 1} : \frac{- 5 + 25 + 4 a}{2}

x = \frac{- 5 - 25 + 4 a}{2 \cdot 1} : \frac{- 5 - 25 + 4 a}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 25 + 4 a}{2}, x = \frac{- 5 - 25 + 4 a}{2}

- 4 x^{2} - 9 = 0

x, x^{2} - 6 x + 13 + y^{2} + 4 y = 0

x, x^{2} + (y - x \frac{2}{3})^{2} = 1

2 (\frac{x + 1}{3})^{2} = \frac{1}{2}

1 \cdot 1 0^{5} [6.666 u^{2} - 3.333 (1.2)] = 6 \cdot 1 0^{5}

What are the solutions to the equation x^2+5x-a=0 ?
The solutions to the equation x^2+5x-a=0 are x=(-5+sqrt(25+4a))/2 ,x=(-5-sqrt(25+4a))/2
Find the zeros of x^2+5x-a=0
The zeros of x^2+5x-a=0 are x=(-5+sqrt(25+4a))/2 ,x=(-5-sqrt(25+4a))/2