What are the solutions to the equation x^2-(sqrt(3)-1)*x-sqrt(3)=0 ?

The solutions to the equation x^2-(sqrt(3)-1)*x-sqrt(3)=0 are x=sqrt(3),x=-1

Find the zeros of x^2-(sqrt(3)-1)*x-sqrt(3)=0

The zeros of x^2-(sqrt(3)-1)*x-sqrt(3)=0 are x=sqrt(3),x=-1

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x^{2} - (3 - 1) \cdot x - 3 = 0

x = 3, x = - 1

Decimal Notation

x = 1.73205 \dots, x = - 1

Solution steps

x^{2} - (3 - 1) x - 3 = 0

Expand

x^{2} - (3 - 1) x - 3 : x^{2} - 3 x + x - 3

x^{2} - 3 x + x - 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + (- 3 + 1) x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 + 1 ) \pm ( - 3 + 1 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 3 + 1)^{2} - 4 \cdot 1 \cdot (- 3) = 3 + 1

x_{1, 2} = \frac{- ( - 3 + 1 ) \pm ( 3 + 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 + 1 ) + 3 + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 + 1 ) - ( 3 + 1 )}{2 \cdot 1}

x = \frac{- ( - 3 + 1 ) + 3 + 1}{2 \cdot 1} : 3

x = \frac{- ( - 3 + 1 ) - ( 3 + 1 )}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

x^{2} - 3 = \frac{( x - 3 )}{2}

1 x^{2} + 20 x = 56

x^{2} - x - b = 0

x, 1^{2} + x^{2} = c \cdot p^{2}

x, 5 x^{2} - 7 x y - 3 y^{2} = 0

What are the solutions to the equation x^2-(sqrt(3)-1)*x-sqrt(3)=0 ?
The solutions to the equation x^2-(sqrt(3)-1)*x-sqrt(3)=0 are x=sqrt(3),x=-1
Find the zeros of x^2-(sqrt(3)-1)*x-sqrt(3)=0
The zeros of x^2-(sqrt(3)-1)*x-sqrt(3)=0 are x=sqrt(3),x=-1