What are the solutions to the equation ((+v)/2)^2=(+v)^2+2(-g)(+30) ?

The solutions to the equation ((+v)/2)^2=(+v)^2+2(-g)(+30) are v=4sqrt(5)sqrt(g),v=-4sqrt(5)sqrt(g)

Find the zeros of ((+v)/2)^2=(+v)^2+2(-g)(+30)

The zeros of ((+v)/2)^2=(+v)^2+2(-g)(+30) are v=4sqrt(5)sqrt(g),v=-4sqrt(5)sqrt(g)

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(\frac{+ v}{2})^{2} = (+ v)^{2} + 2 (- g) (+ 30)

v = 45 g, v = - 45 g

Solution steps

(\frac{v}{2})^{2} = (v)^{2} + 2 (- g) (30)

Move

(+ v)^{2}

to the left side

- \frac{3 v ^{2}}{4} = 2 (- g) \cdot 30

Remove parentheses:

(- a) = - a

- \frac{3 v ^{2}}{4} = - 2 g \cdot 30

Multiply the numbers:

2 \cdot 30 = 60

- \frac{3 v ^{2}}{4} = - 60 g

Multiply both sides by

4

- 3 v^{2} = - 240 g

Divide both sides by

- 3

v^{2} = 80 g

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 80 g, v = - 80 g

Simplify

80 g : 45 g

Simplify

- 80 g : - 45 g

v = 45 g, v = - 45 g

a^{2} - 256 - 15 = 0

(x - 5) (2 x + 5) = 0

x^{2} + 9 x - 3 b = 0

x, 428 x \frac{x}{y} = 12.24

x, p^{2} - y^{2} \cdot q = x^{2} - y^{2}

What are the solutions to the equation ((+v)/2)^2=(+v)^2+2(-g)(+30) ?
The solutions to the equation ((+v)/2)^2=(+v)^2+2(-g)(+30) are v=4sqrt(5)sqrt(g),v=-4sqrt(5)sqrt(g)
Find the zeros of ((+v)/2)^2=(+v)^2+2(-g)(+30)
The zeros of ((+v)/2)^2=(+v)^2+2(-g)(+30) are v=4sqrt(5)sqrt(g),v=-4sqrt(5)sqrt(g)