What are the solutions to the equation (9x^2+3x)/(4+2)=0 ?

The solutions to the equation (9x^2+3x)/(4+2)=0 are x=0,x=-1/3

Find the zeros of (9x^2+3x)/(4+2)=0

The zeros of (9x^2+3x)/(4+2)=0 are x=0,x=-1/3

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\frac{9 x ^{2} + 3 x}{4 + 2} = 0

x = 0, x = - \frac{1}{3}

Decimal Notation

x = 0, x = - 0.33333 \dots

Solution steps

\frac{9 x ^{2} + 3 x}{4 + 2} = 0

Simplify

4 + 2 : 6

\frac{9 x ^{2} + 3 x}{6} = 0

Multiply both sides by

6

9 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

3^{2} - 4 \cdot 9 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 9}, x_{2} = \frac{- 3 - 3}{2 \cdot 9}

x = \frac{- 3 + 3}{2 \cdot 9} : 0

x = \frac{- 3 - 3}{2 \cdot 9} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{3}

\frac{x ^{2}}{2 + 2} = 20

\frac{0.44 x ( x + x \cdot 5 - \frac{23}{55} ) + 3}{14 \cdot 2.24} = 1

48 x^{2} - 13 x - 1 = 0

(k^{2} + 3) \cdot x^{2} + (k^{3} + k + 1) \cdot x + 2 k + 2 = 0

(a + b) 2 x^{2} + 6 (a^{2} - b^{2}) x + 9 (a - b) 2 = 0

What are the solutions to the equation (9x^2+3x)/(4+2)=0 ?
The solutions to the equation (9x^2+3x)/(4+2)=0 are x=0,x=-1/3
Find the zeros of (9x^2+3x)/(4+2)=0
The zeros of (9x^2+3x)/(4+2)=0 are x=0,x=-1/3