What are the solutions to the equation 2x*4x=8,x^1*x^1=8x^2 ?

The solutions to the equation 2x*4x=8,x^1*x^1=8x^2 are x=1,x=-1

Find the zeros of 2x*4x=8,x^1*x^1=8x^2

The zeros of 2x*4x=8,x^1*x^1=8x^2 are x=1,x=-1

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2 x \cdot 4 x = 8, x^{1} \cdot x^{1} = 8 x^{2}

x = 1, x = - 1

Solution steps

2 x \cdot 4 x = 8, x^{1} x^{1} = 8 x^{2}

Simplify

8 x^{2} = 8

Divide both sides by

8

\frac{8 x ^{2}}{8} = \frac{8}{8}

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

c^{2} = 8.41 + 4

3 x^{2} - 26 + 2 = 0

(k - 12) x^{2} + 2 (k - 12) x + 2 = 0

\frac{3 x ^{2} - 4 x}{6} = 20 x

\frac{x ^{2} - x}{12} = 1

What are the solutions to the equation 2x*4x=8,x^1*x^1=8x^2 ?
The solutions to the equation 2x*4x=8,x^1*x^1=8x^2 are x=1,x=-1
Find the zeros of 2x*4x=8,x^1*x^1=8x^2
The zeros of 2x*4x=8,x^1*x^1=8x^2 are x=1,x=-1