What are the solutions to the equation solvefor y,9y^2=x*(3-x)^2 ?

The solutions to the equation solvefor y,9y^2=x*(3-x)^2 are y=(sqrt(x)(3-x))/3 ,y=-(sqrt(x)(3-x))/3

Find the zeros of solvefor y,9y^2=x*(3-x)^2

The zeros of solvefor y,9y^2=x*(3-x)^2 are y=(sqrt(x)(3-x))/3 ,y=-(sqrt(x)(3-x))/3

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solve for

y, 9 y^{2} = x \cdot (3 - x)^{2}

y = \frac{x ( 3 - x )}{3}, y = - \frac{x ( 3 - x )}{3}

Solution steps

9 y^{2} = x (3 - x)^{2}

Divide both sides by

9

y^{2} = \frac{x ( 3 - x ) ^{2}}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{x ( 3 - x ) ^{2}}{9}, y = - \frac{x ( 3 - x ) ^{2}}{9}

Simplify

\frac{x ( 3 - x ) ^{2}}{9} : \frac{x ( 3 - x )}{3}

Simplify

- \frac{x ( 3 - x ) ^{2}}{9} : - \frac{x ( 3 - x )}{3}

y = \frac{x ( 3 - x )}{3}, y = - \frac{x ( 3 - x )}{3}

y (y + 5) = 14

2 x^{2} - 5 x + (3 - k) = 0

x, 4 x^{2} + 6 x y + 4 y^{2} = 1

x^{2} - x (6 - 1) - 6 = 0

x, 2 x^{2} + p^{2} = (q - x)^{2}

What are the solutions to the equation solvefor y,9y^2=x*(3-x)^2 ?
The solutions to the equation solvefor y,9y^2=x*(3-x)^2 are y=(sqrt(x)(3-x))/3 ,y=-(sqrt(x)(3-x))/3
Find the zeros of solvefor y,9y^2=x*(3-x)^2
The zeros of solvefor y,9y^2=x*(3-x)^2 are y=(sqrt(x)(3-x))/3 ,y=-(sqrt(x)(3-x))/3