What are the solutions to the equation 5d^3-d^2-6d=1+x^2 ?

The solutions to the equation 5d^3-d^2-6d=1+x^2 are x=sqrt(5d^3-d^2-6d-1),x=-sqrt(5d^3-d^2-6d-1)

Find the zeros of 5d^3-d^2-6d=1+x^2

The zeros of 5d^3-d^2-6d=1+x^2 are x=sqrt(5d^3-d^2-6d-1),x=-sqrt(5d^3-d^2-6d-1)

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5 d^{3} - d^{2} - 6 d = 1 + x^{2}

x = 5 d^{3} - d^{2} - 6 d - 1, x = - 5 d^{3} - d^{2} - 6 d - 1

Solution steps

5 d^{3} - d^{2} - 6 d = 1 + x^{2}

Switch sides

1 + x^{2} = 5 d^{3} - d^{2} - 6 d

Move

1

to the right side

x^{2} = 5 d^{3} - d^{2} - 6 d - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5 d^{3} - d^{2} - 6 d - 1, x = - 5 d^{3} - d^{2} - 6 d - 1

0.1 n^{2} + 2.5 n - 10 = 0

x, x^{2} - 2^{y} = 23

x, \frac{x}{2} - 3 + 3 x^{2} + x - 6 = (f + g) (x)

x, x \cdot y^{2} + x^{2} \cdot y + 1 = 0

1.5 x^{2} + 2 x = 10

What are the solutions to the equation 5d^3-d^2-6d=1+x^2 ?
The solutions to the equation 5d^3-d^2-6d=1+x^2 are x=sqrt(5d^3-d^2-6d-1),x=-sqrt(5d^3-d^2-6d-1)
Find the zeros of 5d^3-d^2-6d=1+x^2
The zeros of 5d^3-d^2-6d=1+x^2 are x=sqrt(5d^3-d^2-6d-1),x=-sqrt(5d^3-d^2-6d-1)