What are the solutions to the equation solvefor x,x^2-6x-p^2-2p+8=0 ?

The solutions to the equation solvefor x,x^2-6x-p^2-2p+8=0 are x=p+4,x=-p+2

Find the zeros of solvefor x,x^2-6x-p^2-2p+8=0

The zeros of solvefor x,x^2-6x-p^2-2p+8=0 are x=p+4,x=-p+2

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solve for

x, x^{2} - 6 x - p^{2} - 2 p + 8 = 0

x = p + 4, x = - p + 2

Solution steps

x^{2} - 6 x - p^{2} - 2 p + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - p ^{2} - 2 p + 8 )}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot (- p^{2} - 2 p + 8) : 2 (p + 1)

x_{1, 2} = \frac{- ( - 6 ) \pm 2 ( p + 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 ( p + 1 )}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 ( p + 1 )}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 ( p + 1 )}{2 \cdot 1} : p + 4

x = \frac{- ( - 6 ) - 2 ( p + 1 )}{2 \cdot 1} : - p + 2

The solutions to the quadratic equation are:

x = p + 4, x = - p + 2

x, 3 x^{2} + 4 x y + 2 y^{2} = 9

x, (x + a)^{2} + y^{2} = a^{2}

x, x (x + 4 y) - 3 = 0

y, x = \frac{1}{4} p y^{2}

x^{2} + 15 x - 5400 = 0

What are the solutions to the equation solvefor x,x^2-6x-p^2-2p+8=0 ?
The solutions to the equation solvefor x,x^2-6x-p^2-2p+8=0 are x=p+4,x=-p+2
Find the zeros of solvefor x,x^2-6x-p^2-2p+8=0
The zeros of solvefor x,x^2-6x-p^2-2p+8=0 are x=p+4,x=-p+2