What are the solutions to the equation (y+1/4)^2= 6/9 ?

The solutions to the equation (y+1/4)^2= 6/9 are y=sqrt(2/3)-1/4 ,y=-sqrt(2/3)-1/4

Find the zeros of (y+1/4)^2= 6/9

The zeros of (y+1/4)^2= 6/9 are y=sqrt(2/3)-1/4 ,y=-sqrt(2/3)-1/4

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(y + \frac{1}{4})^{2} = \frac{6}{9}

y = \frac{2}{3} - \frac{1}{4}, y = - \frac{2}{3} - \frac{1}{4}

Decimal Notation

y = 0.56649 \dots, y = - 1.06649 \dots

Solution steps

(y + \frac{1}{4})^{2} = \frac{6}{9}

Cancel the common factor:

3

(y + \frac{1}{4})^{2} = \frac{2}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + \frac{1}{4} = \frac{2}{3} : y = \frac{2}{3} - \frac{1}{4}

Solve

y + \frac{1}{4} = - \frac{2}{3} : y = - \frac{2}{3} - \frac{1}{4}

The solutions to the quadratic equation are:

y = \frac{2}{3} - \frac{1}{4}, y = - \frac{2}{3} - \frac{1}{4}

9 + 16 = x^{2}

d = d^{1} - d^{2}

0.75 (0.25 - x + x^{2}) = x^{2}

a = 3 x^{2} - 9 x

x, z = x^{2} - 8 x y + 5 y + 7

What are the solutions to the equation (y+1/4)^2= 6/9 ?
The solutions to the equation (y+1/4)^2= 6/9 are y=sqrt(2/3)-1/4 ,y=-sqrt(2/3)-1/4
Find the zeros of (y+1/4)^2= 6/9
The zeros of (y+1/4)^2= 6/9 are y=sqrt(2/3)-1/4 ,y=-sqrt(2/3)-1/4