What are the solutions to the equation 2x^2+0.4x=0.225 ?

The solutions to the equation 2x^2+0.4x=0.225 are x= 1/4 ,x=-9/20

Find the zeros of 2x^2+0.4x=0.225

The zeros of 2x^2+0.4x=0.225 are x= 1/4 ,x=-9/20

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2 x^{2} + 0.4 x = 0.225

x = \frac{1}{4}, x = - \frac{9}{20}

Decimal Notation

x = 0.25, x = - 0.45

Solution steps

2 x^{2} + 0.4 x = 0.225

Multiply both sides by

1000

2000 x^{2} + 400 x = 225

Move

225

to the left side

2000 x^{2} + 400 x - 225 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 \cdot 2000 ( - 225 )}{2 \cdot 2000}

40 0^{2} - 4 \cdot 2000 (- 225) = 1400

x_{1, 2} = \frac{- 400 \pm 1400}{2 \cdot 2000}

Separate the solutions

x_{1} = \frac{- 400 + 1400}{2 \cdot 2000}, x_{2} = \frac{- 400 - 1400}{2 \cdot 2000}

x = \frac{- 400 + 1400}{2 \cdot 2000} : \frac{1}{4}

x = \frac{- 400 - 1400}{2 \cdot 2000} : - \frac{9}{20}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{9}{20}

2 a^{2} - 8 a + 800 = 0

3 x^{2} - 43 x - 6 = 0

2 x^{2} - 16 x = 12 x + 48

(\frac{5 x - 1}{3})^{2} = \frac{4}{9}

x^{2} + 2 (m + 1) x - 3 m (m - 2) = 0

What are the solutions to the equation 2x^2+0.4x=0.225 ?
The solutions to the equation 2x^2+0.4x=0.225 are x= 1/4 ,x=-9/20
Find the zeros of 2x^2+0.4x=0.225
The zeros of 2x^2+0.4x=0.225 are x= 1/4 ,x=-9/20