What are the solutions to the equation x=5x-4x^2+3 ?

The solutions to the equation x=5x-4x^2+3 are x=-1/2 ,x= 3/2

Find the zeros of x=5x-4x^2+3

The zeros of x=5x-4x^2+3 are x=-1/2 ,x= 3/2

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x = 5 x - 4 x^{2} + 3

x = - \frac{1}{2}, x = \frac{3}{2}

Decimal Notation

x = - 0.5, x = 1.5

Solution steps

x = 5 x - 4 x^{2} + 3

Switch sides

5 x - 4 x^{2} + 3 = x

Move

x

to the left side

- 4 x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

4^{2} - 4 (- 4) \cdot 3 = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 ( - 4 )}, x_{2} = \frac{- 4 - 8}{2 ( - 4 )}

x = \frac{- 4 + 8}{2 ( - 4 )} : - \frac{1}{2}

x = \frac{- 4 - 8}{2 ( - 4 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{3}{2}

x^{2} + (m + 3) \cdot x + (m + 6) = 0

x, (y - 3 x) (x - 8 y) = 0

x, z = 3 \cdot x^{2} - x \cdot y^{2}

l, a = l^{2}

x, x y + x^{2} y^{2} = c

What are the solutions to the equation x=5x-4x^2+3 ?
The solutions to the equation x=5x-4x^2+3 are x=-1/2 ,x= 3/2
Find the zeros of x=5x-4x^2+3
The zeros of x=5x-4x^2+3 are x=-1/2 ,x= 3/2