What are the solutions to the equation solvefor a,(99)^2=(a+b)^2 ?

The solutions to the equation solvefor a,(99)^2=(a+b)^2 are a=99-b,a=-99-b

Find the zeros of solvefor a,(99)^2=(a+b)^2

The zeros of solvefor a,(99)^2=(a+b)^2 are a=99-b,a=-99-b

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solve for

a, (99)^{2} = (a + b)^{2}

a = 99 - b, a = - 99 - b

Solution steps

(99)^{2} = (a + b)^{2}

Switch sides

(a + b)^{2} = 9 9^{2}

9 9^{2} = 9801

(a + b)^{2} = 9801

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a + b = 9801 : a = 99 - b

Solve

a + b = - 9801 : a = - 99 - b

The solutions to the quadratic equation are:

a = 99 - b, a = - 99 - b

m, x^{6} + 9 x^{4} + 24 m^{2} + 16 = 0

x^{3} - 3 x^{2} + 5 x = (x - 2)^{3}

x, f = x^{2} - k - r

5 \cdot x^{2} - x = 0

x^{2} + x - a (a + 1) = 0

What are the solutions to the equation solvefor a,(99)^2=(a+b)^2 ?
The solutions to the equation solvefor a,(99)^2=(a+b)^2 are a=99-b,a=-99-b
Find the zeros of solvefor a,(99)^2=(a+b)^2
The zeros of solvefor a,(99)^2=(a+b)^2 are a=99-b,a=-99-b