What are the solutions to the equation x^2+x-a(a+1)=0 ?

The solutions to the equation x^2+x-a(a+1)=0 are x=a,x=-a-1

Find the zeros of x^2+x-a(a+1)=0

The zeros of x^2+x-a(a+1)=0 are x=a,x=-a-1

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x^{2} + x - a (a + 1) = 0

x = a, x = - a - 1

Solution steps

x^{2} + x - a (a + 1) = 0

Expand

x^{2} + x - a (a + 1) : x^{2} + x - a^{2} - a

x^{2} + x - a^{2} - a = 0

Factor

x^{2} + x - a^{2} - a : (x - a) (x + a + 1)

(x - a) (x + a + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - a = 0 or x + a + 1 = 0

Solve

x - a = 0 : x = a

Solve

x + a + 1 = 0 : x = - a - 1

The solutions to the quadratic equation are:

x = a, x = - a - 1

x, (x - 1)^{2} + (y - 1)^{2} = \frac{( x - y - 3 ) ^{2}}{2}

\frac{x ^{2} + x}{( 2 ) + 1} = 0

(d^{3} - 3 d - 2) = x^{2}

14 x^{1} - 3 x^{2} = 8, x^{1} + 5 x^{2} = 11

y, y^{2} = x (x^{2} - 3)

What are the solutions to the equation x^2+x-a(a+1)=0 ?
The solutions to the equation x^2+x-a(a+1)=0 are x=a,x=-a-1
Find the zeros of x^2+x-a(a+1)=0
The zeros of x^2+x-a(a+1)=0 are x=a,x=-a-1