What are the solutions to the equation solvefor y,y^2=x(x^2-3) ?

The solutions to the equation solvefor y,y^2=x(x^2-3) are y=sqrt(x)sqrt(x^2-3),y=-sqrt(x)sqrt(x^2-3)

Find the zeros of solvefor y,y^2=x(x^2-3)

The zeros of solvefor y,y^2=x(x^2-3) are y=sqrt(x)sqrt(x^2-3),y=-sqrt(x)sqrt(x^2-3)

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solve for

y, y^{2} = x (x^{2} - 3)

y = x x^{2} - 3, y = - x x^{2} - 3

Solution steps

y^{2} = x (x^{2} - 3)

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x (x^{2} - 3), y = - x (x^{2} - 3)

Simplify

x (x^{2} - 3) : x x^{2} - 3

Simplify

- x (x^{2} - 3) : - x x^{2} - 3

y = x x^{2} - 3, y = - x x^{2} - 3

a^{2} b^{2} x^{2} + b^{2} x - a^{2} x - 1 = 0

100 t^{2} - 192 t + 256 = 0

\frac{a}{b} = k^{2}

x, j = (4 + 3 x) (8 x + s)

x, x - y = 4 y^{3} - 3 x^{2}

What are the solutions to the equation solvefor y,y^2=x(x^2-3) ?
The solutions to the equation solvefor y,y^2=x(x^2-3) are y=sqrt(x)sqrt(x^2-3),y=-sqrt(x)sqrt(x^2-3)
Find the zeros of solvefor y,y^2=x(x^2-3)
The zeros of solvefor y,y^2=x(x^2-3) are y=sqrt(x)sqrt(x^2-3),y=-sqrt(x)sqrt(x^2-3)