What are the solutions to the equation a/b =k^2 ?

The solutions to the equation a/b =k^2 are k=sqrt(a/b),k=-sqrt(a/b)

Find the zeros of a/b =k^2

The zeros of a/b =k^2 are k=sqrt(a/b),k=-sqrt(a/b)

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\frac{a}{b} = k^{2}

k = \frac{a}{b}, k = - \frac{a}{b}

Solution steps

\frac{a}{b} = k^{2}

Switch sides

k^{2} = \frac{a}{b}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = \frac{a}{b}, k = - \frac{a}{b}

x, j = (4 + 3 x) (8 x + s)

x, x - y = 4 y^{3} - 3 x^{2}

(4 a)^{2} + (3 a)^{2} = 12 5^{2}

- 72 = - 18 x^{2}

(q) = 3 q^{2} + 5 q + 10

What are the solutions to the equation a/b =k^2 ?
The solutions to the equation a/b =k^2 are k=sqrt(a/b),k=-sqrt(a/b)
Find the zeros of a/b =k^2
The zeros of a/b =k^2 are k=sqrt(a/b),k=-sqrt(a/b)