What are the solutions to the equation (5x^2)/6 = 40/3 ?

The solutions to the equation (5x^2)/6 = 40/3 are x=4,x=-4

Find the zeros of (5x^2)/6 = 40/3

The zeros of (5x^2)/6 = 40/3 are x=4,x=-4

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\frac{5 x ^{2}}{6} = \frac{40}{3}

x = 4, x = - 4

Solution steps

\frac{5 x ^{2}}{6} = \frac{40}{3}

Multiply both sides by

6

5 x^{2} = 80

Divide both sides by

5

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

x, z (x) = 8 x^{2} - 5 x + 9

(x + 1) (x + 2) = (x - 7) (- 2)

(\frac{x}{2 - 1}) (\frac{3 x - 2}{4 - 5}) = 0

x^{2} - \frac{11}{4} x + \frac{15}{8} = 0

x, x^{2} + y^{2} + 4 y + 13 = 6 x

What are the solutions to the equation (5x^2)/6 = 40/3 ?
The solutions to the equation (5x^2)/6 = 40/3 are x=4,x=-4
Find the zeros of (5x^2)/6 = 40/3
The zeros of (5x^2)/6 = 40/3 are x=4,x=-4