What are the solutions to the equation u^2+n+1=0 ?

The solutions to the equation u^2+n+1=0 are u=sqrt(-n-1),u=-sqrt(-n-1)

Find the zeros of u^2+n+1=0

The zeros of u^2+n+1=0 are u=sqrt(-n-1),u=-sqrt(-n-1)

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u^{2} + n + 1 = 0

u = - n - 1, u = - - n - 1

Solution steps

u^{2} + n + 1 = 0

Move

n

to the right side

u^{2} + 1 = - n

Move

1

to the right side

u^{2} = - n - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = - n - 1, u = - - n - 1

x, x^{2} + y^{2} - 2 y = - 1

6 n^{2} - 11 n - 726 = 0

y, y^{2} - y = x^{3} - x

x^{2} = 0.36

\frac{( x + 3 ) ( x - 1 )}{3} = \frac{( 5 x - 10 )}{2}

What are the solutions to the equation u^2+n+1=0 ?
The solutions to the equation u^2+n+1=0 are u=sqrt(-n-1),u=-sqrt(-n-1)
Find the zeros of u^2+n+1=0
The zeros of u^2+n+1=0 are u=sqrt(-n-1),u=-sqrt(-n-1)