What are the solutions to the equation x(x+7)=(2x-1)(x+4) ?

The solutions to the equation x(x+7)=(2x-1)(x+4) are x=2,x=-2

Find the zeros of x(x+7)=(2x-1)(x+4)

The zeros of x(x+7)=(2x-1)(x+4) are x=2,x=-2

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x (x + 7) = (2 x - 1) (x + 4)

x = 2, x = - 2

Solution steps

x (x + 7) = (2 x - 1) (x + 4)

Expand

x (x + 7) : x^{2} + 7 x

Expand

(2 x - 1) (x + 4) : 2 x^{2} + 7 x - 4

x^{2} + 7 x = 2 x^{2} + 7 x - 4

Move

7 x

to the left side

x^{2} = 2 x^{2} - 4

Move

2 x^{2}

to the left side

- x^{2} = - 4

Divide both sides by

- 1

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

9.5 x + 2.5 x \cdot (1 - x) = 3.95

100 x^{2} - 3 = 20 x

4 (x^{2} - 1) = 0

2 (a + 5) \cdot x^{2} - (a + 5) \cdot x + 1 = 0

a, (1 + a + b)^{2} = 3 (a^{2} + b^{2} + 1)

What are the solutions to the equation x(x+7)=(2x-1)(x+4) ?
The solutions to the equation x(x+7)=(2x-1)(x+4) are x=2,x=-2
Find the zeros of x(x+7)=(2x-1)(x+4)
The zeros of x(x+7)=(2x-1)(x+4) are x=2,x=-2