What are the solutions to the equation 60=-16t^2+70t+5 ?

The solutions to the equation 60=-16t^2+70t+5 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)

Find the zeros of 60=-16t^2+70t+5

The zeros of 60=-16t^2+70t+5 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)

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60 = - 16 t^{2} + 70 t + 5

t = \frac{35 - 345}{16}, t = \frac{35 + 345}{16}

Solution steps

60 = - 16 t^{2} + 70 t + 5

Switch sides

- 16 t^{2} + 70 t + 5 = 60

Move

60

to the left side

- 16 t^{2} + 70 t - 55 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 ( - 16 ) ( - 55 )}{2 ( - 16 )}

7 0^{2} - 4 (- 16) (- 55) = 2345

t_{1, 2} = \frac{- 70 \pm 2 345}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 70 + 2 345}{2 ( - 16 )}, t_{2} = \frac{- 70 - 2 345}{2 ( - 16 )}

t = \frac{- 70 + 2 345}{2 ( - 16 )} : \frac{35 - 345}{16}

t = \frac{- 70 - 2 345}{2 ( - 16 )} : \frac{35 + 345}{16}

The solutions to the quadratic equation are:

t = \frac{35 - 345}{16}, t = \frac{35 + 345}{16}

\frac{9 !}{3 ! ( 9 - 3 ) !}

3 (x - 3) + 44 = - 2 x

\frac{1}{2} 78

(- \frac{64}{27})^{\frac{1}{3}}

18 y + 5 y^{2} = 35

What are the solutions to the equation 60=-16t^2+70t+5 ?
The solutions to the equation 60=-16t^2+70t+5 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)
Find the zeros of 60=-16t^2+70t+5
The zeros of 60=-16t^2+70t+5 are t=(35-sqrt(345))/(16),t=(35+sqrt(345))/(16)