What are the solutions to the equation (t)=576+64t-t^2 ?

The solutions to the equation (t)=576+64t-t^2 are t=-(-63+3sqrt(697))/2 ,t=(63+3sqrt(697))/2

Find the zeros of (t)=576+64t-t^2

The zeros of (t)=576+64t-t^2 are t=-(-63+3sqrt(697))/2 ,t=(63+3sqrt(697))/2

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(t) = 576 + 64 t - t^{2}

t = - \frac{- 63 + 3 697}{2}, t = \frac{63 + 3 697}{2}

Decimal Notation

t = - 8.10113 \dots, t = 71.10113 \dots

Solution steps

(t) = 576 + 64 t - t^{2}

Refine

t = 576 + 64 t - t^{2}

Switch sides

576 + 64 t - t^{2} = t

Move

t

to the left side

- t^{2} + 63 t + 576 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 63 \pm 6 3 ^{2} - 4 ( - 1 ) \cdot 576}{2 ( - 1 )}

6 3^{2} - 4 (- 1) \cdot 576 = 3697

t_{1, 2} = \frac{- 63 \pm 3 697}{2 ( - 1 )}

Separate the solutions

t_{1} = \frac{- 63 + 3 697}{2 ( - 1 )}, t_{2} = \frac{- 63 - 3 697}{2 ( - 1 )}

t = \frac{- 63 + 3 697}{2 ( - 1 )} : - \frac{- 63 + 3 697}{2}

t = \frac{- 63 - 3 697}{2 ( - 1 )} : \frac{63 + 3 697}{2}

The solutions to the quadratic equation are:

t = - \frac{- 63 + 3 697}{2}, t = \frac{63 + 3 697}{2}

4 x^{2} - 24 x + 5 = 0

x, z = 2 x y - x^{2} - 2 y^{2} + 4 y

h, 2 h^{2} + o^{2} = 2 h^{2} o

0.25 x^{2} + 0.75 x - 0.1875 = 0

a^{0.2} x (7 x + 5) - 7 x (2 x - 3) = 93

What are the solutions to the equation (t)=576+64t-t^2 ?
The solutions to the equation (t)=576+64t-t^2 are t=-(-63+3sqrt(697))/2 ,t=(63+3sqrt(697))/2
Find the zeros of (t)=576+64t-t^2
The zeros of (t)=576+64t-t^2 are t=-(-63+3sqrt(697))/2 ,t=(63+3sqrt(697))/2