What are the solutions to the equation x^2+(3-2a)x-6a=0 ?

The solutions to the equation x^2+(3-2a)x-6a=0 are x=2a,x=-3

Find the zeros of x^2+(3-2a)x-6a=0

The zeros of x^2+(3-2a)x-6a=0 are x=2a,x=-3

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x^{2} + (3 - 2 a) x - 6 a = 0

x = 2 a, x = - 3

Solution steps

x^{2} + (3 - 2 a) x - 6 a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 3 - 2 a ) \pm ( 3 - 2 a ) ^{2} - 4 \cdot 1 \cdot ( - 6 a )}{2 \cdot 1}

Simplify

(3 - 2 a)^{2} - 4 \cdot 1 \cdot (- 6 a) : 2 a + 3

x_{1, 2} = \frac{- ( 3 - 2 a ) \pm ( 2 a + 3 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( 3 - 2 a ) + 2 a + 3}{2 \cdot 1}, x_{2} = \frac{- ( 3 - 2 a ) - ( 2 a + 3 )}{2 \cdot 1}

x = \frac{- ( 3 - 2 a ) + 2 a + 3}{2 \cdot 1} : 2 a

x = \frac{- ( 3 - 2 a ) - ( 2 a + 3 )}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2 a, x = - 3

9.8 = 4.9 t^{2}

0.2 x^{2} - 0.5 x - 1.2 = 0

(n) = \frac{n ^{2}}{2} - 3 \frac{n}{2}

x^{2} - x + 1 = 0, x = 1 x = - 1

x, 2 x \cdot (6 x - 2 y^{2}) + 3 y^{2} (x - 4) = 8

What are the solutions to the equation x^2+(3-2a)x-6a=0 ?
The solutions to the equation x^2+(3-2a)x-6a=0 are x=2a,x=-3
Find the zeros of x^2+(3-2a)x-6a=0
The zeros of x^2+(3-2a)x-6a=0 are x=2a,x=-3