What are the solutions to the equation 3x^2+7x+4x=0 ?

The solutions to the equation 3x^2+7x+4x=0 are x=0,x=-11/3

Find the zeros of 3x^2+7x+4x=0

The zeros of 3x^2+7x+4x=0 are x=0,x=-11/3

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3 x^{2} + 7 x + 4 x = 0

x = 0, x = - \frac{11}{3}

Decimal Notation

x = 0, x = - 3.66666 \dots

Solution steps

3 x^{2} + 7 x + 4 x = 0

Refine

3 x^{2} + 11 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 0 = 11

x_{1, 2} = \frac{- 11 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 11}{2 \cdot 3}, x_{2} = \frac{- 11 - 11}{2 \cdot 3}

x = \frac{- 11 + 11}{2 \cdot 3} : 0

x = \frac{- 11 - 11}{2 \cdot 3} : - \frac{11}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{11}{3}

t, e = v_{c} \cdot t - \frac{1}{2} \cdot a \cdot t^{2}

- 6 x^{2} = - 72

54 = \frac{n ^{2} - 3 n}{2}

3 - 2 x + x^{2} = 0

x, a \cdot y = x^{2} + 2 (x + 1)

What are the solutions to the equation 3x^2+7x+4x=0 ?
The solutions to the equation 3x^2+7x+4x=0 are x=0,x=-11/3
Find the zeros of 3x^2+7x+4x=0
The zeros of 3x^2+7x+4x=0 are x=0,x=-11/3