What are the solutions to the equation (5x+8)(7x-5)=0 ?

The solutions to the equation (5x+8)(7x-5)=0 are x=-8/5 ,x= 5/7

Find the zeros of (5x+8)(7x-5)=0

The zeros of (5x+8)(7x-5)=0 are x=-8/5 ,x= 5/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5 x + 8) (7 x - 5) = 0

x = - \frac{8}{5}, x = \frac{5}{7}

Decimal Notation

x = - 1.6, x = 0.71428 \dots

Solution steps

(5 x + 8) (7 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 8 = 0 or 7 x - 5 = 0

Solve

5 x + 8 = 0 : x = - \frac{8}{5}

Solve

7 x - 5 = 0 : x = \frac{5}{7}

The solutions to the quadratic equation are:

x = - \frac{8}{5}, x = \frac{5}{7}

a = 34 x^{2} + x

r^{2} = (\frac{a}{2})^{2} + (\frac{a}{2})^{2}

- 14 = 5 n - n^{2}

2 x^{2} + 3 x + c = 0

a^{2} + 5 a + 4 = 0

What are the solutions to the equation (5x+8)(7x-5)=0 ?
The solutions to the equation (5x+8)(7x-5)=0 are x=-8/5 ,x= 5/7
Find the zeros of (5x+8)(7x-5)=0
The zeros of (5x+8)(7x-5)=0 are x=-8/5 ,x= 5/7