What are the solutions to the equation r^2=(a/2)^2+(a/2)^2 ?

The solutions to the equation r^2=(a/2)^2+(a/2)^2 are r= a/(sqrt(2)),r=-a/(sqrt(2))

Find the zeros of r^2=(a/2)^2+(a/2)^2

The zeros of r^2=(a/2)^2+(a/2)^2 are r= a/(sqrt(2)),r=-a/(sqrt(2))

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r^{2} = (\frac{a}{2})^{2} + (\frac{a}{2})^{2}

r = \frac{a}{2}, r = - \frac{a}{2}

Solution steps

r^{2} = (\frac{a}{2})^{2} + (\frac{a}{2})^{2}

Simplify

(\frac{a}{2})^{2} + (\frac{a}{2})^{2} : \frac{a ^{2}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{a ^{2}}{2}, r = - \frac{a ^{2}}{2}

Simplify

\frac{a ^{2}}{2} : \frac{a}{2}

Simplify

- \frac{a ^{2}}{2} : - \frac{a}{2}

r = \frac{a}{2}, r = - \frac{a}{2}

- 14 = 5 n - n^{2}

2 x^{2} + 3 x + c = 0

a^{2} + 5 a + 4 = 0

x, x^{2} + x - p (p + 1) = 0

(7) \cdot 2 \cdot x^{2} + 7 x + 52 = 0

What are the solutions to the equation r^2=(a/2)^2+(a/2)^2 ?
The solutions to the equation r^2=(a/2)^2+(a/2)^2 are r= a/(sqrt(2)),r=-a/(sqrt(2))
Find the zeros of r^2=(a/2)^2+(a/2)^2
The zeros of r^2=(a/2)^2+(a/2)^2 are r= a/(sqrt(2)),r=-a/(sqrt(2))