What are the solutions to the equation 2p+p^2=1358 ?

The solutions to the equation 2p+p^2=1358 are p=-1+3sqrt(151),p=-1-3sqrt(151)

Find the zeros of 2p+p^2=1358

The zeros of 2p+p^2=1358 are p=-1+3sqrt(151),p=-1-3sqrt(151)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 p + p^{2} = 1358

p = - 1 + 3151, p = - 1 - 3151

Decimal Notation

p = 35.86461 \dots, p = - 37.86461 \dots

Solution steps

2 p + p^{2} = 1358

Move

1358

to the left side

2 p + p^{2} - 1358 = 0

Write in the standard form

a x^{2} + b x + c = 0

p^{2} + 2 p - 1358 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1358 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1358) = 6151

p_{1, 2} = \frac{- 2 \pm 6 151}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 2 + 6 151}{2 \cdot 1}, p_{2} = \frac{- 2 - 6 151}{2 \cdot 1}

p = \frac{- 2 + 6 151}{2 \cdot 1} : - 1 + 3151

p = \frac{- 2 - 6 151}{2 \cdot 1} : - 1 - 3151

The solutions to the quadratic equation are:

p = - 1 + 3151, p = - 1 - 3151

x^{2} + (m - 1) \cdot x + 2 m - 6 = 0

x^{2} = - 3, x^{1} = 7

25 m^{2} - 54 m + 128 = 0

a, a^{2} + b^{2} - 2 (3 a + 2 b) + 13 = 0

x, x^{2} + 25 y^{2} - 2 x + 10 y + 2 = 0

What are the solutions to the equation 2p+p^2=1358 ?
The solutions to the equation 2p+p^2=1358 are p=-1+3sqrt(151),p=-1-3sqrt(151)
Find the zeros of 2p+p^2=1358
The zeros of 2p+p^2=1358 are p=-1+3sqrt(151),p=-1-3sqrt(151)