What are the solutions to the equation x^2+(m-1)*x+2m-6=0 ?

The solutions to the equation x^2+(m-1)*x+2m-6=0 are x=-2,x=-m+3

Find the zeros of x^2+(m-1)*x+2m-6=0

The zeros of x^2+(m-1)*x+2m-6=0 are x=-2,x=-m+3

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x^{2} + (m - 1) \cdot x + 2 m - 6 = 0

x = - 2, x = - m + 3

Solution steps

x^{2} + (m - 1) x + 2 m - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( m - 1 ) \pm ( m - 1 ) ^{2} - 4 \cdot 1 \cdot ( 2 m - 6 )}{2 \cdot 1}

Simplify

(m - 1)^{2} - 4 \cdot 1 \cdot (2 m - 6) : m - 5

x_{1, 2} = \frac{- ( m - 1 ) \pm ( m - 5 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( m - 1 ) + m - 5}{2 \cdot 1}, x_{2} = \frac{- ( m - 1 ) - ( m - 5 )}{2 \cdot 1}

x = \frac{- ( m - 1 ) + m - 5}{2 \cdot 1} : - 2

x = \frac{- ( m - 1 ) - ( m - 5 )}{2 \cdot 1} : - m + 3

The solutions to the quadratic equation are:

x = - 2, x = - m + 3

x^{2} = - 3, x^{1} = 7

25 m^{2} - 54 m + 128 = 0

a, a^{2} + b^{2} - 2 (3 a + 2 b) + 13 = 0

x, x^{2} + 25 y^{2} - 2 x + 10 y + 2 = 0

(\frac{( x + 5 )}{5}) \cdot (\frac{( x - 6 )}{7}) = 6

What are the solutions to the equation x^2+(m-1)*x+2m-6=0 ?
The solutions to the equation x^2+(m-1)*x+2m-6=0 are x=-2,x=-m+3
Find the zeros of x^2+(m-1)*x+2m-6=0
The zeros of x^2+(m-1)*x+2m-6=0 are x=-2,x=-m+3