What are the solutions to the equation -y^2+35y=306 ?

The solutions to the equation -y^2+35y=306 are y=17,y=18

Find the zeros of -y^2+35y=306

The zeros of -y^2+35y=306 are y=17,y=18

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- y^{2} + 35 y = 306

y = 17, y = 18

Solution steps

- y^{2} + 35 y = 306

Move

306

to the left side

- y^{2} + 35 y - 306 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 ( - 1 ) ( - 306 )}{2 ( - 1 )}

3 5^{2} - 4 (- 1) (- 306) = 1

y_{1, 2} = \frac{- 35 \pm 1}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- 35 + 1}{2 ( - 1 )}, y_{2} = \frac{- 35 - 1}{2 ( - 1 )}

y = \frac{- 35 + 1}{2 ( - 1 )} : 17

y = \frac{- 35 - 1}{2 ( - 1 )} : 18

The solutions to the quadratic equation are:

y = 17, y = 18

\frac{5}{2} x + \frac{2}{3} x = \frac{95}{2} x^{2}

x, 2 x^{2} + 4 y^{2} + 4 x + 4 x y + 1 = 2 x

(d) 2 x^{2} - 5 x = (x - 1)^{2}

a = - x^{2} + 4 x + 2

x, f = (2 x - 1)^{2} + 3

What are the solutions to the equation -y^2+35y=306 ?
The solutions to the equation -y^2+35y=306 are y=17,y=18
Find the zeros of -y^2+35y=306
The zeros of -y^2+35y=306 are y=17,y=18