What are the solutions to the equation n=0.25t^2-6t+84 ?

The solutions to the equation n=0.25t^2-6t+84 are t=2(sqrt(n-48)+6),t=2(-sqrt(n-48)+6)

Find the zeros of n=0.25t^2-6t+84

The zeros of n=0.25t^2-6t+84 are t=2(sqrt(n-48)+6),t=2(-sqrt(n-48)+6)

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n = 0.25 t^{2} - 6 t + 84

t = 2 (n - 48 + 6), t = 2 (- n - 48 + 6)

Solution steps

n = 0.25 t^{2} - 6 t + 84

Multiply both sides by

100

n \cdot 100 = 25 t^{2} - 600 t + 8400

Switch sides

25 t^{2} - 600 t + 8400 = n \cdot 100

Move

n 100

to the left side

25 t^{2} - 600 t + 8400 - n \cdot 100 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 600 ) \pm ( - 600 ) ^{2} - 4 \cdot 25 ( 8400 - n \cdot 100 )}{2 \cdot 25}

Simplify

(- 600)^{2} - 4 \cdot 25 (8400 - n \cdot 100) : 100 n - 48

t_{1, 2} = \frac{- ( - 600 ) \pm 100 n - 48}{2 \cdot 25}

Separate the solutions

t_{1} = \frac{- ( - 600 ) + 100 n - 48}{2 \cdot 25}, t_{2} = \frac{- ( - 600 ) - 100 n - 48}{2 \cdot 25}

t = \frac{- ( - 600 ) + 100 n - 48}{2 \cdot 25} : 2 (n - 48 + 6)

t = \frac{- ( - 600 ) - 100 n - 48}{2 \cdot 25} : 2 (- n - 48 + 6)

The solutions to the quadratic equation are:

t = 2 (n - 48 + 6), t = 2 (- n - 48 + 6)

(x^{1})^{2} = 1

4 x^{2} - 4 a^{2} x + (a - b) = 0

x, p (x + 1) = x^{2} + p

a, u = 50 a - 0.5 a^{2} + 60 m - 0.25 m^{2}

(a - b) \cdot x^{2} + (b + c - a) x - c = 0

What are the solutions to the equation n=0.25t^2-6t+84 ?
The solutions to the equation n=0.25t^2-6t+84 are t=2(sqrt(n-48)+6),t=2(-sqrt(n-48)+6)
Find the zeros of n=0.25t^2-6t+84
The zeros of n=0.25t^2-6t+84 are t=2(sqrt(n-48)+6),t=2(-sqrt(n-48)+6)