What is (-8a^8b^{-2})/(10a^{-4)b^{-10}} ?

The solution to (-8a^8b^{-2})/(10a^{-4)b^{-10}} is -(4a^{12}b^8)/5

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simplify (-8a^8b^{-2})/(10a^{-4)b^{-10}}

simplify

\frac{- 8 a ^{8} b ^{- 2}}{10 a ^{- 4} b ^{- 10}}

- \frac{4 a ^{12} b ^{8}}{5}

Solution steps

\frac{- 8 a ^{8} b ^{- 2}}{10 a ^{- 4} b ^{- 10}}

Factor the number:

8 = 2 \cdot 4

= \frac{- 2 \cdot 4 a ^{8} b ^{- 2}}{10 a ^{- 4} b ^{- 10}}

Factor the number:

10 = 2 \cdot 5

= \frac{- 2 \cdot 4 a ^{8} b ^{- 2}}{2 \cdot 5 a ^{- 4} b ^{- 10}}

Cancel the common factor:

2

= \frac{- 4 a ^{8} b ^{- 2}}{5 a ^{- 4} b ^{- 10}}

Simplify

\frac{a ^{8}}{a ^{- 4}} : a^{12}

= \frac{- 4 a ^{12} b ^{- 2}}{5 b ^{- 10}}

Simplify

\frac{b ^{- 2}}{b ^{- 10}} : b^{8}

= \frac{- 4 a ^{12} b ^{8}}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4 a ^{12} b ^{8}}{5}

- 2 x^{2} + 12 x - 11 = 0

p^{2} + 9 p - 36

\frac{3 r}{5} - 1 > \frac{2}{5}

(- 4 x)^{- 3}

What is (-8a^8b^{-2})/(10a^{-4)b^{-10}} ?
The solution to (-8a^8b^{-2})/(10a^{-4)b^{-10}} is -(4a^{12}b^8)/5