What are the solutions to the equation x^2+(98-m)^2=41 ?

The solutions to the equation x^2+(98-m)^2=41 are x=sqrt(-m^2+196m-9563),x=-sqrt(-m^2+196m-9563)

Find the zeros of x^2+(98-m)^2=41

The zeros of x^2+(98-m)^2=41 are x=sqrt(-m^2+196m-9563),x=-sqrt(-m^2+196m-9563)

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x^{2} + (98 - m)^{2} = 41

x = - m^{2} + 196 m - 9563, x = - - m^{2} + 196 m - 9563

Solution steps

x^{2} + (98 - m)^{2} = 41

Move

(98 - m)^{2}

to the right side

x^{2} = 41 - (98 - m)^{2}

Simplify

41 - (98 - m)^{2} : - m^{2} + 196 m - 9563

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - m^{2} + 196 m - 9563, x = - - m^{2} + 196 m - 9563

x, 4 x^{2} + 2 y^{2} = 4 x y - 2 y - 1

x^{2} - 60 x - 2700 = 0

x, (x + y)^{2} = 4

4. 5^{2} = x^{2} + 3^{2}

y^{2} - 36 \cdot 2 = 1

What are the solutions to the equation x^2+(98-m)^2=41 ?
The solutions to the equation x^2+(98-m)^2=41 are x=sqrt(-m^2+196m-9563),x=-sqrt(-m^2+196m-9563)
Find the zeros of x^2+(98-m)^2=41
The zeros of x^2+(98-m)^2=41 are x=sqrt(-m^2+196m-9563),x=-sqrt(-m^2+196m-9563)