What are the solutions to the equation (x)=x^2-40x+500 ?

The solutions to the equation (x)=x^2-40x+500 are x= 41/2+i(sqrt(319))/2 ,x= 41/2-i(sqrt(319))/2

Find the zeros of (x)=x^2-40x+500

The zeros of (x)=x^2-40x+500 are x= 41/2+i(sqrt(319))/2 ,x= 41/2-i(sqrt(319))/2

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(x) = x^{2} - 40 x + 500

x = \frac{41}{2} + i \frac{319}{2}, x = \frac{41}{2} - i \frac{319}{2}

Solution steps

(x) = x^{2} - 40 x + 500

Refine

x = x^{2} - 40 x + 500

Switch sides

x^{2} - 40 x + 500 = x

Move

x

to the left side

x^{2} - 41 x + 500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 1 \cdot 500}{2 \cdot 1}

Simplify

(- 41)^{2} - 4 \cdot 1 \cdot 500 : 319 i

x_{1, 2} = \frac{- ( - 41 ) \pm 319 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 319 i}{2 \cdot 1}, x_{2} = \frac{- ( - 41 ) - 319 i}{2 \cdot 1}

x = \frac{- ( - 41 ) + 319 i}{2 \cdot 1} : \frac{41}{2} + i \frac{319}{2}

x = \frac{- ( - 41 ) - 319 i}{2 \cdot 1} : \frac{41}{2} - i \frac{319}{2}

The solutions to the quadratic equation are:

x = \frac{41}{2} + i \frac{319}{2}, x = \frac{41}{2} - i \frac{319}{2}

(3 x + 6) (x + 6) = 231

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4 x^{2} - 10 x + 2 = 0

x^{2} + 6 x - (a^{2} + 2 a - 8) = 0

x (x \frac{1}{3}) = 27

What are the solutions to the equation (x)=x^2-40x+500 ?
The solutions to the equation (x)=x^2-40x+500 are x= 41/2+i(sqrt(319))/2 ,x= 41/2-i(sqrt(319))/2
Find the zeros of (x)=x^2-40x+500
The zeros of (x)=x^2-40x+500 are x= 41/2+i(sqrt(319))/2 ,x= 41/2-i(sqrt(319))/2