What are the solutions to the equation x^2+6x-(a^2+2a-8)=0 ?

The solutions to the equation x^2+6x-(a^2+2a-8)=0 are x=a-2,x=-a-4

Find the zeros of x^2+6x-(a^2+2a-8)=0

The zeros of x^2+6x-(a^2+2a-8)=0 are x=a-2,x=-a-4

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x^{2} + 6 x - (a^{2} + 2 a - 8) = 0

x = a - 2, x = - a - 4

Solution steps

x^{2} + 6 x - (a^{2} + 2 a - 8) = 0

Expand

x^{2} + 6 x - (a^{2} + 2 a - 8) : x^{2} + 6 x - a^{2} - 2 a + 8

x^{2} + 6 x - a^{2} - 2 a + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - a ^{2} - 2 a + 8 )}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot (- a^{2} - 2 a + 8) : 2 (a + 1)

x_{1, 2} = \frac{- 6 \pm 2 ( a + 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 ( a + 1 )}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 ( a + 1 )}{2 \cdot 1}

x = \frac{- 6 + 2 ( a + 1 )}{2 \cdot 1} : a - 2

x = \frac{- 6 - 2 ( a + 1 )}{2 \cdot 1} : - a - 4

The solutions to the quadratic equation are:

x = a - 2, x = - a - 4

x (x \frac{1}{3}) = 27

x^{2} - 2 (k + 1) x + k^{2} = 0

a^{2} = x^{2} + (\frac{a}{2})^{2}

3.9 = x^{2} + 3.6

x, y^{2} - 6 y = (x + 3)^{2} - 9

What are the solutions to the equation x^2+6x-(a^2+2a-8)=0 ?
The solutions to the equation x^2+6x-(a^2+2a-8)=0 are x=a-2,x=-a-4
Find the zeros of x^2+6x-(a^2+2a-8)=0
The zeros of x^2+6x-(a^2+2a-8)=0 are x=a-2,x=-a-4