What are the solutions to the equation a^2=x^2+(a/2)^2 ?

The solutions to the equation a^2=x^2+(a/2)^2 are x=(sqrt(3)a)/2 ,x=-(sqrt(3)a)/2

Find the zeros of a^2=x^2+(a/2)^2

The zeros of a^2=x^2+(a/2)^2 are x=(sqrt(3)a)/2 ,x=-(sqrt(3)a)/2

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a^{2} = x^{2} + (\frac{a}{2})^{2}

x = \frac{3 a}{2}, x = - \frac{3 a}{2}

Solution steps

a^{2} = x^{2} + (\frac{a}{2})^{2}

Expand

x^{2} + (\frac{a}{2})^{2} : x^{2} + \frac{a ^{2}}{4}

a^{2} = x^{2} + \frac{a ^{2}}{4}

Switch sides

x^{2} + \frac{a ^{2}}{4} = a^{2}

Move

\frac{a ^{2}}{4}

to the right side

x^{2} = a^{2} - \frac{a ^{2}}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = a^{2} - \frac{a ^{2}}{4}, x = - a^{2} - \frac{a ^{2}}{4}

Simplify

a^{2} - \frac{a ^{2}}{4} : \frac{3 a}{2}

Simplify

- a^{2} - \frac{a ^{2}}{4} : - \frac{3 a}{2}

x = \frac{3 a}{2}, x = - \frac{3 a}{2}

3.9 = x^{2} + 3.6

x, y^{2} - 6 y = (x + 3)^{2} - 9

y, 2 x^{3} + 2 y - 3 y^{2} = 13 x

m, m^{2} = 3 n

x, 6 x^{2} - 11 x y + 3 y^{2} = 0

What are the solutions to the equation a^2=x^2+(a/2)^2 ?
The solutions to the equation a^2=x^2+(a/2)^2 are x=(sqrt(3)a)/2 ,x=-(sqrt(3)a)/2
Find the zeros of a^2=x^2+(a/2)^2
The zeros of a^2=x^2+(a/2)^2 are x=(sqrt(3)a)/2 ,x=-(sqrt(3)a)/2