What are the solutions to the equation 7x^2-12x+18=0 ?

The solutions to the equation 7x^2-12x+18=0 are x= 6/7+i(3sqrt(10))/7 ,x= 6/7-i(3sqrt(10))/7

Find the zeros of 7x^2-12x+18=0

The zeros of 7x^2-12x+18=0 are x= 6/7+i(3sqrt(10))/7 ,x= 6/7-i(3sqrt(10))/7

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7 x^{2} - 12 x + 18 = 0

x = \frac{6}{7} + i \frac{3 10}{7}, x = \frac{6}{7} - i \frac{3 10}{7}

Solution steps

7 x^{2} - 12 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 7 \cdot 18}{2 \cdot 7}

Simplify

(- 12)^{2} - 4 \cdot 7 \cdot 18 : 610 i

x_{1, 2} = \frac{- ( - 12 ) \pm 6 10 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 10 i}{2 \cdot 7}, x_{2} = \frac{- ( - 12 ) - 6 10 i}{2 \cdot 7}

x = \frac{- ( - 12 ) + 6 10 i}{2 \cdot 7} : \frac{6}{7} + i \frac{3 10}{7}

x = \frac{- ( - 12 ) - 6 10 i}{2 \cdot 7} : \frac{6}{7} - i \frac{3 10}{7}

The solutions to the quadratic equation are:

x = \frac{6}{7} + i \frac{3 10}{7}, x = \frac{6}{7} - i \frac{3 10}{7}

a^{2} \cdot (x - b) - b^{2} \cdot (x - a) = x^{2} (a - b)

x, 6 x^{2} - x y - 12 y^{2} - 8 x + 29 y - 14 = 0

x^{2} + 3 = 311

x, x^{2} - x y + 4 y = 3

x, 2 x^{2} - x y + 7 x + 2 y - y^{2} - 7 = 0

What are the solutions to the equation 7x^2-12x+18=0 ?
The solutions to the equation 7x^2-12x+18=0 are x= 6/7+i(3sqrt(10))/7 ,x= 6/7-i(3sqrt(10))/7
Find the zeros of 7x^2-12x+18=0
The zeros of 7x^2-12x+18=0 are x= 6/7+i(3sqrt(10))/7 ,x= 6/7-i(3sqrt(10))/7