What are the solutions to the equation 3x^2+5x-1300=0 ?

The solutions to the equation 3x^2+5x-1300=0 are x=20,x=-65/3

Find the zeros of 3x^2+5x-1300=0

The zeros of 3x^2+5x-1300=0 are x=20,x=-65/3

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3 x^{2} + 5 x - 1300 = 0

x = 20, x = - \frac{65}{3}

Decimal Notation

x = 20, x = - 21.66666 \dots

Solution steps

3 x^{2} + 5 x - 1300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 1300 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 1300) = 125

x_{1, 2} = \frac{- 5 \pm 125}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 125}{2 \cdot 3}, x_{2} = \frac{- 5 - 125}{2 \cdot 3}

x = \frac{- 5 + 125}{2 \cdot 3} : 20

x = \frac{- 5 - 125}{2 \cdot 3} : - \frac{65}{3}

The solutions to the quadratic equation are:

x = 20, x = - \frac{65}{3}

d = (x + 4)^{2} + (2 x + 1) (2 x - 1) - 3 x (\frac{x - 1}{3})

p, p^{2} + (x - e^{x}) p - e^{x} = 0

- 8 h^{2} + l_{1} + 6 h \cdot l_{1} = 0

- 5 x^{2} + 34 x - 24 = 0

x^{1} + 2 x^{2} = 5

What are the solutions to the equation 3x^2+5x-1300=0 ?
The solutions to the equation 3x^2+5x-1300=0 are x=20,x=-65/3
Find the zeros of 3x^2+5x-1300=0
The zeros of 3x^2+5x-1300=0 are x=20,x=-65/3