What are the solutions to the equation 5x(3x+2x)-3x=40 ?

The solutions to the equation 5x(3x+2x)-3x=40 are x=(3+sqrt(4009))/(50),x=(3-sqrt(4009))/(50)

Find the zeros of 5x(3x+2x)-3x=40

The zeros of 5x(3x+2x)-3x=40 are x=(3+sqrt(4009))/(50),x=(3-sqrt(4009))/(50)

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5 x (3 x + 2 x) - 3 x = 40

x = \frac{3 + 4009}{50}, x = \frac{3 - 4009}{50}

Decimal Notation

x = 1.32633 \dots, x = - 1.20633 \dots

Solution steps

5 x (3 x + 2 x) - 3 x = 40

Expand

5 x (3 x + 2 x) - 3 x : 25 x^{2} - 3 x

25 x^{2} - 3 x = 40

Move

40

to the left side

25 x^{2} - 3 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 25 ( - 40 )}{2 \cdot 25}

(- 3)^{2} - 4 \cdot 25 (- 40) = 4009

x_{1, 2} = \frac{- ( - 3 ) \pm 4009}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 4009}{2 \cdot 25}, x_{2} = \frac{- ( - 3 ) - 4009}{2 \cdot 25}

x = \frac{- ( - 3 ) + 4009}{2 \cdot 25} : \frac{3 + 4009}{50}

x = \frac{- ( - 3 ) - 4009}{2 \cdot 25} : \frac{3 - 4009}{50}

The solutions to the quadratic equation are:

x = \frac{3 + 4009}{50}, x = \frac{3 - 4009}{50}

x, (p - 3) \cdot x^{2} - 2 (p - 3) x + 2 = 0

(a - 1) x^{2} + (3 - a) x + b = 0

k, k 8 k + 2 m = 3 m + k

x, x^{2} - (t - 1) x + t - 2 = 0

x^{2} - (7 + 3) \cdot x + 6 (1 + 3) = 0

What are the solutions to the equation 5x(3x+2x)-3x=40 ?
The solutions to the equation 5x(3x+2x)-3x=40 are x=(3+sqrt(4009))/(50),x=(3-sqrt(4009))/(50)
Find the zeros of 5x(3x+2x)-3x=40
The zeros of 5x(3x+2x)-3x=40 are x=(3+sqrt(4009))/(50),x=(3-sqrt(4009))/(50)