What are the solutions to the equation (x-5)(x-6)=(25)/(24^2) ?

The solutions to the equation (x-5)(x-6)=(25)/(24^2) are x= 145/24 ,x= 119/24

Find the zeros of (x-5)(x-6)=(25)/(24^2)

The zeros of (x-5)(x-6)=(25)/(24^2) are x= 145/24 ,x= 119/24

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(x - 5) (x - 6) = \frac{25}{2 4 ^{2}}

x = \frac{145}{24}, x = \frac{119}{24}

Decimal Notation

x = 6.04166 \dots, x = 4.95833 \dots

Solution steps

(x - 5) (x - 6) = \frac{25}{2 4 ^{2}}

Simplify

2 4^{2} : 576

(x - 5) (x - 6) = \frac{25}{576}

Multiply both sides by

576

576 (x - 5) (x - 6) = 25

Expand

576 (x - 5) (x - 6) : 576 x^{2} - 6336 x + 17280

576 x^{2} - 6336 x + 17280 = 25

Move

25

to the left side

576 x^{2} - 6336 x + 17255 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6336 ) \pm ( - 6336 ) ^{2} - 4 \cdot 576 \cdot 17255}{2 \cdot 576}

(- 6336)^{2} - 4 \cdot 576 \cdot 17255 = 624

x_{1, 2} = \frac{- ( - 6336 ) \pm 624}{2 \cdot 576}

Separate the solutions

x_{1} = \frac{- ( - 6336 ) + 624}{2 \cdot 576}, x_{2} = \frac{- ( - 6336 ) - 624}{2 \cdot 576}

x = \frac{- ( - 6336 ) + 624}{2 \cdot 576} : \frac{145}{24}

x = \frac{- ( - 6336 ) - 624}{2 \cdot 576} : \frac{119}{24}

The solutions to the quadratic equation are:

x = \frac{145}{24}, x = \frac{119}{24}

46 \cdot x^{2} - 13 x - 26 = 0

x, a = (4 x + y)^{2}

(x - 1) (x^{2} - x + 1) = x^{3} - 1

(3 x)^{2} - 2 = 1

x, \frac{( x ^{2} + m ^{2} )}{v} = \frac{( v ^{2} - s )}{m}

What are the solutions to the equation (x-5)(x-6)=(25)/(24^2) ?
The solutions to the equation (x-5)(x-6)=(25)/(24^2) are x= 145/24 ,x= 119/24
Find the zeros of (x-5)(x-6)=(25)/(24^2)
The zeros of (x-5)(x-6)=(25)/(24^2) are x= 145/24 ,x= 119/24