What is the answer to 3*2^x=(1/3)*4^x ?

The answer to 3*2^x=(1/3)*4^x is x=(2ln(3))/(ln(2))

Solve for x: 3*2^x=(1/3)*4^x

The solution is x=(2ln(3))/(ln(2))

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3 \cdot 2^{x} = (\frac{1}{3}) \cdot 4^{x}

x = \frac{2 ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = 3.16992 \dots

Solution steps

3 \cdot 2^{x} = (\frac{1}{3}) \cdot 4^{x}

Apply exponent rules

ln (3) + x ln (2) = ln (\frac{1}{3}) + 2 x ln (2)

Solve

ln (3) + x ln (2) = ln (\frac{1}{3}) + 2 x ln (2) : x = \frac{2 ln ( 3 )}{ln ( 2 )}

x = \frac{2 ln ( 3 )}{ln ( 2 )}

3^{x} + 9^{x} = 2 7^{x}

4^{x} + 6^{x} = 9^{x}

3^{x} + 3^{1 - x} = 4

3^{x} = 3^{6}

x, 3^{x} + 3^{y} = 10

What is the answer to 3*2^x=(1/3)*4^x ?
The answer to 3*2^x=(1/3)*4^x is x=(2ln(3))/(ln(2))
Solve for x: 3*2^x=(1/3)*4^x
The solution is x=(2ln(3))/(ln(2))