What is the answer to 3^{2x}=6^{x-2} ?

The answer to 3^{2x}=6^{x-2} is x=-(2ln(6))/(ln(3/2))

Solve for x: 3^{2x}=6^{x-2}

The solution is x=-(2ln(6))/(ln(3/2))

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3^{2 x} = 6^{x - 2}

x = - \frac{2 ln ( 6 )}{ln ( \frac{3}{2} )}

Decimal Notation

x = - 8.83804 \dots

Solution steps

3^{2 x} = 6^{x - 2}

Apply exponent rules

2 x ln (3) = (x - 2) ln (6)

Solve

2 x ln (3) = (x - 2) ln (6) : x = - \frac{2 ln ( 6 )}{ln ( \frac{3}{2} )}

x = - \frac{2 ln ( 6 )}{ln ( \frac{3}{2} )}

(- 10)^{x} = 1000

3^{x} = 0

∣ 2^{x} - 1 ∣ + ∣ 2^{x} + 1 ∣ = 2

x, \frac{1 0 ^{x}}{1 0 ^{y}} = 100

x = 2^{x}

What is the answer to 3^{2x}=6^{x-2} ?
The answer to 3^{2x}=6^{x-2} is x=-(2ln(6))/(ln(3/2))
Solve for x: 3^{2x}=6^{x-2}
The solution is x=-(2ln(6))/(ln(3/2))