What are the solutions to the equation 3x^2-7=0 ?

The solutions to the equation 3x^2-7=0 are x=sqrt(7/3),x=-sqrt(7/3)

Find the zeros of 3x^2-7=0

The zeros of 3x^2-7=0 are x=sqrt(7/3),x=-sqrt(7/3)

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3 x^{2} - 7 = 0

x = \frac{7}{3}, x = - \frac{7}{3}

Decimal Notation

x = 1.52752 \dots, x = - 1.52752 \dots

Solution steps

3 x^{2} - 7 = 0

Move

7

to the right side

3 x^{2} = 7

Divide both sides by

3

x^{2} = \frac{7}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{3}, x = - \frac{7}{3}

\frac{π}{4} - \frac{1}{2}

x^{2} + 18 x + 4 = 0

cos^{2} (x) - sin^{2} (x)

\frac{m ^{\frac{3}{2}}}{4 m ^{\frac{3}{2}}}

2^{18}

What are the solutions to the equation 3x^2-7=0 ?
The solutions to the equation 3x^2-7=0 are x=sqrt(7/3),x=-sqrt(7/3)
Find the zeros of 3x^2-7=0
The zeros of 3x^2-7=0 are x=sqrt(7/3),x=-sqrt(7/3)