What is the answer to 5^{2x^2-3x-2}=1 ?

The answer to 5^{2x^2-3x-2}=1 is x=-1/2 ,x=2

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5^{2x^2-3x-2}=1

5^{2 x^{2} - 3 x - 2} = 1

x = - \frac{1}{2}, x = 2

Decimal Notation

x = - 0.5, x = 2

Solution steps

5^{2 x^{2} - 3 x - 2} = 1

Apply exponent rules

(2 x^{2} - 3 x - 2) ln (5) = ln (1)

Solve

(2 x^{2} - 3 x - 2) ln (5) = ln (1) : x = - \frac{1}{2}, x = 2

x = - \frac{1}{2}, x = 2

8^{x} = 16

2^{3 x + 1} = 3^{x - 2}

5^{x} = 8

4^{x} + 1 6^{x} = 272

2^{x + 2} - 2^{x} = 4

What is the answer to 5^{2x^2-3x-2}=1 ?
The answer to 5^{2x^2-3x-2}=1 is x=-1/2 ,x=2
Solve for x: 5^{2x^2-3x-2}=1
The solution is x=-1/2 ,x=2