What is the answer to (16^x)^2=8^{4x-3} ?

The answer to (16^x)^2=8^{4x-3} is x= 9/4

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(16^x)^2=8^{4x-3}

(1 6^{x})^{2} = 8^{4 x - 3}

x = \frac{9}{4}

Decimal Notation

x = 2.25

Solution steps

(1 6^{x})^{2} = 8^{4 x - 3}

Apply exponent rules

8 x = 3 (4 x - 3)

Solve

8 x = 3 (4 x - 3) : x = \frac{9}{4}

x = \frac{9}{4}

25 6^{a} + 25 6^{a} + 1 6^{a} = 1

4^{x} - 2 = 2^{6} x

3^{x - 1} = \frac{1}{2 ^{x + 5}}

2^{(x + 2) (x^{2} - 5 x + 6)} = 1

16 (2.9)^{x} = (6.4)^{x}

What is the answer to (16^x)^2=8^{4x-3} ?
The answer to (16^x)^2=8^{4x-3} is x= 9/4
Solve for x: (16^x)^2=8^{4x-3}
The solution is x= 9/4