What is the answer to ((7^{3-2x}))/((7^{7-5x))}=49^{3x-14} ?

The answer to ((7^{3-2x}))/((7^{7-5x))}=49^{3x-14} is x=8

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((7^{3-2x}))/((7^{7-5x))}=49^{3x-14}

\frac{( 7 ^{3 - 2 x} )}{( 7 ^{7 - 5 x} )} = 4 9^{3 x - 14}

x = 8

Solution steps

\frac{( 7 ^{3 - 2 x} )}{( 7 ^{7 - 5 x} )} = 4 9^{3 x - 14}

Apply exponent rules

3 x - 4 = 2 (3 x - 14)

Solve

3 x - 4 = 2 (3 x - 14) : x = 8

x = 8

Verify Solutions:

x = 8

True

The solution is

x = 8

(3^{4})^{x} = 5

1 = 3^{2 x}

\frac{e ^{- t \cdot 1000}}{41.3} = 1

9^{x} - 3^{x} - 72 = 0

\frac{3 ^{x} + 3}{( 3 ^{x} )} = 4

What is the answer to ((7^{3-2x}))/((7^{7-5x))}=49^{3x-14} ?
The answer to ((7^{3-2x}))/((7^{7-5x))}=49^{3x-14} is x=8
Solve for x: ((7^{3-2x}))/((7^{7-5x))}=49^{3x-14}
The solution is x=8